New random number loop

Projects Programming
2

one solution is put all numbers in an array, scramble them and take the first 5.

  int numbers[] = { 0,1,2,3,4,5,6,7,8,9,10,11,12,13 };
  int count = 13;


void setup()
{
  Serial.begin(9600);
  
  scrambleArray(numbers, count);
  for (int i=0; i<count; i++)
  {
    Serial.println(numbers[i]);
  }
  Serial.println("----");
}

void loop()
{}

void scrambleArray(int * array, int size)
{
  int last = 0;
  int temp = array[last];
  for (int i=0; i<size; i++)
  {
    int index = random(size);
    array[last] = array[index];
    last = index;
  }
  array[last] = temp;
}

Another solution is to remember the values you got "thrown", if one is already in the list rethrow the dice ...