Just had a quick question regarding NPN transistors, forgive my i am a mece and just started learning electronics…
My question is this, when you are running an npn transistor in saturation mode (Vc << Vb , ie. closed switch). Do you still get a 0.6 V drop from the base voltage to emitter? Or do you pretty much ignore it, and treat the collector emmiter as a closed switch and all the voltage drops, current depend on your Vc, and any resistors attached in that line?
Also, how close or how much lower does Vc have to be than Vb to run in saturation??