It is correct that an opamp with lower bandwidth will reproduce a signal with a low peak input voltage - say 125mV. Where as if I have a 5V peak signal, i would need a much higher slew rate? Slew rate= (2piF*Vpk/1e-6)[V/us]
I have an signal source that gives me 5V peak, 68Mhz square wave at a very low output impedance. I wanted a buffer op amp to help interface it to other things. If I use a fraction of the input voltage, that requires a lower slew rate and I can get away with a lower bandwidth op-amp. Is that correct?