It is better to post graphics as JPG or GIF files.
Just to be clear:
12V to pins 4 and 8
Ground to pin 1
Pins 2, 6, and 7 connected to C1
But you should be looking at the top of C1 for the sawtooth wave. All you’ll see on the output is 12V interrupted by a very short downward spike. See my math below to see just how long that will take with the values selected.
The Control voltage pin should have something more like a 1nF capacitor. If you use a CMOS 555 timer, it may take a while for a 0.2uF cap to charge on startup, although after that it won’t matter. For the simulation, you can leave it off.
100k and 10uF is a bit slow.
(12-0.7)/100k = 113uA
C1 must charge from 1/3 of Vcc to 2/3 of Vcc, so 4V differential.
V = It/C
t = VC/I
t = 4 * 113u / 10u
t = 45.2 seconds
In a real-world circuit, a generic aluminum electrolytic may have so much leakage current, that the circuit never charges.
This will be a linear function of the resistance, and an inverse linear function of the capacitance. So use a 0.1uF capacitor, and the period will be 0.452 seconds. With a 0.1uF capacitor and 10k, 45.2ms.