With what you posted last the voltage at A is always going to be the voltage at Vin. They are connected to the same point in the circuit so how could it be any different?
Remember the A/D in the Arduino is 10 bits, that means 1024 steps. With a 5V reference the steps are going to be 5/1024 V or 4.88mV.
The current down the chain is Vin / (1M + 10K + 200R ) = Vin/ 1010200 A or if Vin is 5V then the current is 4.96uA, lets call it 5uA.
So across the 200R resistor you will develop a voltage drop of 0.001V - about a fifth of a step from the A/D
Across the 10K you have 0.05V or about 10 steps.
Do you think that is viable for a design?