I tryed to attach the pic but it was too large, so I'm going to write the scheme.
Vin = 5V = V arduino;
Then, I've 3 resistence: A= 220ohm, B= 10kohm, C= 1Mohm.
So, applying the rules for a voltage divider, we obtain that the voltage on the resistence A is given by the formula:
V(A) = VinA/(A+B+C) = 5220/(220+10^3 + 10^6) = 0.001V = 1mV.
Repeating this for B and C we obtain that:
V(B) = 0.005V = 5mV
and
V(C) = 4.99V
Converting voltage to values of arduino we obtain that:
n(V(A)): 5:1024=0.001:n => n= 0.2 => n=0 (because of the numbers converted are INT);
n(V(B)): 5:1024=0.005:n => n= 1.02 => n=1 (" " " ");
n(V(C)): 5:1024=4.99:n => n=1021.9 => n=1021 ( " " " ");
what now, raschemmel?