for (i=0; i<511; i++) {
k = 1023sin(2pi*f/i);
}[/quote]
Divide by zero. And the time difference between samples, since it is 1/i, will not be constant.
Pete
for (i=0; i<511; i++) {
k = 1023sin(2pi*f/i);
}[/quote]
Divide by zero. And the time difference between samples, since it is 1/i, will not be constant.
Pete