Pointer Memory Address

Using Arduino Programming Questions
#1

I'm writing some code to check my understanding of pointers & arrays.

This output comes from the code below:

Address[0]: 536903648
Address[1]: 536903652
Value[0]: 0
Value[1]: 1
Value[0]: 1

My question is: if int's are 2-bytes, why isn't Address[1] 536903650 ?

int i[2] = {0,1};
int *p = i;
Serial.print(F("Address[0]: "));
Serial.println((long)i, DEC);
Serial.print(F("Address[1]: "));
Serial.println((long)(i + 1), DEC);
Serial.print(F("Value[0]: "));
Serial.println(*p, DEC);
Serial.print(F("Value[1]: "));
Serial.println(*(p + 1), DEC);
*p++;
Serial.print(F("Value[1]: "));
Serial.println(*p, DEC);
#2

What’s the processor?

#3

because int is 4 bytes on your MCU

#4

I think your question has already pointed (excuse the pun) me to the answer.

The sketch is running on a Teensy 3.2 which is a 32-bit Arduino-Compatible Microcontroller.

An int on this machine must be 4-bytes long.

#5