Power Monitoring with Current Transducers

Hi, I've been working on a project to use current transducers to monitor my home energy consumption. My project is based upon this project: http://www.picobay.com/projects/2009/01/real-time-web-based-power-charting.html , which was using ioBridge as a gateway, not an Arduino.

In short, I've been using a current clamp that outputs 10mV/Amp, and using a AD627 instrument amplifier (DIP package) to boost the voltages that the Arduino sees.

This is the schematic I've been using: http://www.picobay.com/projects/uploaded_images/Schematic-752398.png (I changed out the AD8220 for a AD627, the pin mappings were a little different).

I can measure the output of the circuit that I'm taking into the Arduino's A0 pin using a multimeter, and I have it adjusted to give 1.00v DC on the nose. However, measuring through the arduino, I'm getting 1.09v as my baseline. Since sensitivity is a priority, this .09v difference ends up converting to 200-something watts. Maybe someone can take a look to see what I can improve upon?

void setup() {
  Serial.begin(9600);
  analogReference(DEFAULT);
}

void loop() {
  delay(1000);
  
  //get the analog reading
  float analog_1 = analogRead(A0);    
  Serial.print("Analog Reading: ");
  Serial.print(analog_1);
  Serial.print(", ");
  
  //convert the analog reading to voltage, using 5v = 1024
  float ct1_value = (analog_1 * 5) / 1024;
  Serial.print("Converted to Voltage: ");
  Serial.print(ct1_value);
  Serial.print(", ");
  
  //Because the circuit outputs 1v at a 0 reading, calculate the current. In the 
  //circuit, a 16k resistor is used to create a gain of 4  
  float amps_1 = ((ct1_value -1) * 100)/4;
  
  //Convert over to watts, using a 75% power conversion, and a 110vac house voltage
  float watts_1 = 110 * amps_1 * .75;
  
  Serial.print(amps_1);
  Serial.print("a   ");
  Serial.print(watts_1);
  Serial.println(" watts");  
 
}

5V/1024 gives u a resolution of 4.88mV...

furthermore u possibly have less than 5V as ur ADC's Vref...
can u measure the voltage that ur arduino uses?

What's D1 in that circuit supposed to be doing?

D1 and C1 are providing basic rectification from AC (which is what is being measured and then amplified) to DC for the input.