print.BYTE and 'sto.1b8b'

hi there

i use the shift in code in tutorial, i wanna make 64 switches controller but the data received in max
is a list ‘1 0 1 0 1’
but i wanna make it into number like: ‘10101’

the other option for me is change the data form in arduino code so i can send BYTE data (like 128, 72…etc) but not BIN data directly to max, so i can decode it with sto.1b8b in max/msp.

another things: below is code for 16 switches, any one can show how i fix it into 64 switches?

thx!! ::slight_smile:

//define where your pins are
int latchPin = 8;
int dataPin = 9;
int clockPin = 7;

//Define variables to hold the data
//for each shift register.
//starting with non-zero numbers can help
byte switchVar1 = 72; //01001000
byte switchVar2 = 159; //10011111

void setup() {
//start serial

//define pin modes
pinMode(latchPin, OUTPUT);
pinMode(clockPin, OUTPUT);
pinMode(dataPin, INPUT);


void loop() {

//Pulse the latch pin:
//set it to 1 to collect parallel data
//set it to 1 to collect parallel data, wait
//set it to 0 to transmit data serially

//while the shift register is in serial mode
//collect each shift register into a byte
//the register attached to the chip comes in first
switchVar1 = shiftIn(dataPin, clockPin);
switchVar2 = shiftIn(dataPin, clockPin);

//Print out the results.
//leading 0’s at the top of the byte
//(7, 6, 5, etc) will be dropped before
//the first pin that has a high input
Serial.print(switchVar1, BIN);
Serial.print(switchVar2, BIN);


//------------------------------------------------end main loop

////// ----------------------------------------shiftIn function
///// just needs the location of the data pin and the clock pin
///// it returns a byte with each bit in the byte corresponding
///// to a pin on the shift register. leftBit 7 = Pin 7 / Bit 0= Pin 0

byte shiftIn(int myDataPin, int myClockPin) {
int i;
int temp = 0;
int pinState;
byte myDataIn = 0;

pinMode(myClockPin, OUTPUT);
pinMode(myDataPin, INPUT);

//we will be holding the clock pin high 8 times (0,…,7) at the
//end of each time through the for loop

//at the begining of each loop when we set the clock low, it will
//be doing the necessary low to high drop to cause the shift
//register’s DataPin to change state based on the value
//of the next bit in its serial information flow.
//The register transmits the information about the pins from pin 7 to pin 0
//so that is why our function counts down
for (i=7; i>=0; i–)
digitalWrite(myClockPin, 0);
temp = digitalRead(myDataPin);
if (temp) {
pinState = 1;
//set the bit to 0 no matter what
myDataIn = myDataIn | (1 << i);
else {
//turn it off – only necessary for debuging
//print statement since myDataIn starts as 0
pinState = 0;

//Debuging print statements
//Serial.print(" ");
//Serial.println (dataIn, BIN);

digitalWrite(myClockPin, 1);

//debuging print statements whitespace
//Serial.println(myDataIn, BIN);
return myDataIn;