Print command with SerialOpen

Using Arduino Programming Questions
#1

Hello,

On version 0.22, with Serial.begin(9600), I used Serial.println("Test") without any problem, however it does not work with SerialOpen(0,9600) on verson 1.0

Could someone tell me why, and a correct print command with using SerialOpen ?

Thanks Eaton

#2

What is SerialOpen?

#3

Sorry, forgot to attach the function defined

void SerialOpen(uint8_t port, uint32_t baud) {
uint8_t h = ((F_CPU / 4 / baud -1) / 2) >> 8;
uint8_t l = ((F_CPU / 4 / baud -1) / 2);
switch (port) {
case 0: UCSR0A = (1<<U2X0); UBRR0H = h; UBRR0L = l; UCSR0B |= (1<<RXEN0)|(1<<TXEN0)|(1<<RXCIE0); break;
#if defined(MEGA)
case 1: UCSR1A = (1<<U2X1); UBRR1H = h; UBRR1L = l; UCSR1B |= (1<<RXEN1)|(1<<TXEN1)|(1<<RXCIE1); break;
case 2: UCSR2A = (1<<U2X2); UBRR2H = h; UBRR2L = l; UCSR2B |= (1<<RXEN2)|(1<<TXEN2)|(1<<RXCIE2); break;
case 3: UCSR3A = (1<<U2X3); UBRR3H = h; UBRR3L = l; UCSR3B |= (1<<RXEN3)|(1<<TXEN3)|(1<<RXCIE3); break;
#endif
}
}

#4

Okay. That still doesn't explain what SerialOpen is. I don't know what it is or how it relates to the Arduino Serial library.

#5

Why have you written (or borrowed) this convoluted function that will only work on one kind of Arduino? What is wrong with using the Serial.begin() method in 1.0?

#6