Print distance and speed on one line

Projects Programming
1

Hi, my question is: i have 2 codes that are working but uses 2 print lines. On the print monitor the value are:
35
21

Is there away they print on one line like: 35, 21?
Thanks

2 
Serial.print (35);
Serial.print (',');
Serial.println (21);
3 
Serial.print(distance);
Serial.print(',');
Serial.println(speed);

Too slow :woozy_face:

4

// defines pins numbers
const int trigPin = 9;
const int echoPin = 10;

// defines variables
long duration;
int FirstDistance=0;
int SecondDistance=0;
double speed=0;
int distance=1;
float Time = 2.0;
float delayedtime = 1000*Time;

void setup()
{

pinMode(trigPin, OUTPUT); // Sets the trigPin as an Output
pinMode(echoPin, INPUT); // Sets the echoPin as an Input

Serial.begin(9600); // Starts the serial communication

}

void loop()
{
GetSpeed();

}

float GetDistance()
{
// Clears the trigPin
digitalWrite(trigPin, LOW);
delayMicroseconds(2);

// Sets the trigPin on HIGH state for 10 micro seconds
digitalWrite(trigPin, HIGH);
delayMicroseconds(10);
digitalWrite(trigPin, LOW);

// Reads the echoPin, returns the sound wave travel time in microseconds
duration = pulseIn(echoPin, HIGH);

//calculating distance
distance= duration*0.034/2;

// Prints the distance on the Serial Monitor
Serial.print("Distance in cm : ");
Serial.println(distance);

return distance;

}
void GetSpeed(){

FirstDistance = GetDistance(); //get the first distance

delay(delayedtime); //waits 2 seconds depending on the time declared above ,, feel free to change the value dependng on the resolution of your sensor

SecondDistance = GetDistance(); //gets the second distance

speed = (FirstDistance - SecondDistance)/Time; // now calculating the difference

//printing the speed on the serial monitor
Serial.print("the speed (cm/s) is : ");
Serial.println(speed);

}
float ultrasonicRead ()
{
// Clears the trigPin
digitalWrite(trigPin, LOW);
delayMicroseconds(2);

// Sets the trigPin on HIGH state for 10 micro seconds
digitalWrite(trigPin, HIGH);
delayMicroseconds(10);
digitalWrite(trigPin, LOW);

// Reads the echoPin, returns the sound wave travel time in microseconds
duration = pulseIn(echoPin, HIGH);

//calculating distance
distance= duration*0.034/2;

Serial.println("Arrows, Distance, 0");

{
// Prints the distance on the Serial Monitor
Serial.print("Arrows, Distance, ");
Serial.println(distance);
}
return distance;

}

5

so what will the code be to have everything on one line?

6

See replies #2 and #3

Please remember to use code tags when posting code.

7

Sorry it is my first time and new with this

8

Read the forum guidelines to see how to properly post code and some information on how to get the most from this forum.
Use the IDE autoformat tool (ctrl-t or Tools, Auto format) before posting code in code tags.

Everything? Of what does everything consist? Give us an example of how it should look and identify the parts.

9

(Uncompiled, untested)

// defines pins numbers
const byte trigPin = 9;
const byte echoPin = 10;

unsigned long Time = 2;
unsigned long delayedtime = 1000*Time;

void setup()
{
  pinMode(trigPin, OUTPUT); // Sets the trigPin as an Output
  digitalWrite (trigPin, LOW);
  pinMode(echoPin, INPUT); // Sets the echoPin as an Input

  Serial.begin(9600); // Starts the serial communication
}

void loop()
{
  GetSpeed();
}

float GetDistance()
{
  digitalWrite(trigPin, HIGH);
  delayMicroseconds(10);
  digitalWrite(trigPin, LOW);

  unsigned long duration = pulseIn(echoPin, HIGH);

  return duration*0.034/2;
}

void GetSpeed()
{
  float FirstDistance = GetDistance(); //get the first distance
  Serial.print("First Distance in cm : ");
  Serial.print(FirstDistance);

  delay(delayedtime);
  
  float SecondDistance = GetDistance(); //gets the second distance
  Serial.print(" Second Distance in cm : ");
  Serial.print(SecondDistance);

  float speed = (FirstDistance - SecondDistance)/Time; // now calculating the difference

  //printing the speed on the serial monitor
  Serial.print(" the speed (cm/s) is : ");
  Serial.println(speed);
}
10

Yes, thank you, and sorry for the mistake. It was my first time. Thanks again it works!

11

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