Print integer by index?

Projects Programming
1

Hey Creators,

I want to know if I can print or assign integer value by indexing like array.

Ex.: m=56;

c=m[0];

b=m[1];

Thank You!

2

No. c=m/10; b=m%10

An integer is not a string and does not have an array index reference as a simple type.

3

thedarknight:
I want to know if I can print or assign integer value by indexing like array.

of course you can set the value of a integer to the value of an array element.

but "m" is not an array. you could translate it to a string and then set "chars" to specific chars in the string using an index

   int  m = 56;
    char s [10];
    sprintf (s, "%d", m);

    char c = s [0];
    char b = s [1];

    char t [20];
    sprintf (t, " c %c, b %c", c, b);
    Serial.println (t);
4

another method if you don't mind indexing from right to left...

// function to extract a single digit from an int

uint8_t extract( long num, uint8_t index, uint8_t base = 10 )
{
  return  static_cast<uint8_t>( num /  pow(base, index) ) % base;
}

void setup()
{

  Serial.begin(115200 );

  int m=56;
  Serial.println( extract( m, 1 ) );
  Serial.println( extract( m, 0 ) );
  Serial.println();
  Serial.println( extract(0xABCD, 2, HEX ), HEX ); // just to demonstrate using a different number base

}
void loop() {}