Printing floating point numbers in serial

Projects Programming
1

I am using this code I found in this forum:

void printDouble( double val, unsigned int precision){
// prints val with number of decimal places determine by precision
// NOTE: precision is 1 followed by the number of zeros for the desired number of decimial places
// example: printDouble( 3.1415, 100); // prints 3.14 (two decimal places)

   Serial.print (int(val));  //prints the int part
   Serial.print("."); // print the decimal point
   unsigned int frac;
   if(val >= 0)
     frac = (val - int(val)) * precision;
   else
      frac = (int(val)- val ) * precision;
   int frac1 = frac;
   while( frac1 /= 10 )
       precision /= 10;
   precision /= 10;
   while(  precision /= 10)
       Serial.print("0");

   Serial.println(frac,DEC) ;
}

But I get this error on my program:

test.ino:25: error: cannot convert 'float (*)()' to 'double' for argument '1' to 'void printDouble(double, unsigned int)'

            printDouble(read_temperature,10000000);

How can I fix this?

3

Yes it is a function that returns float.

You don't get 10000000 decimal of precision. You only get a decimal number with 7 digits precision!

6

You do realise, I hope, that Serial supports printing float values?

7

But I get this error on my program:

But you didn't post your program.
We get that a lot.

"360modena_cs"

I'm hoping the "_cs" doesn't imply "computer science"

8

No! it does not mean computer science.
Thanks a lot!