Problem converting chars to uint8_t array

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1

Hi guys , i have a problem wit conversion ..

i need to send a message via esp_now function this is the function : i know the uint8_t is like a byte definition and is like an unsigned char
the declaration of the function is :

esp_now_send(const uint8_t *peer_addr, const uint8_t *data, size_t len);

void sendData(char * datos) {

uint8_t data =( uint8_t*)datos; // i try to cast char to uint8_t

for (int i = 0; i < SlaveCnt; i++) {
const uint8_t peer_addr = slaves.peer_addr;*

  • if (i == 0) { // print only for first slave*

  • esp_err_t result = esp_now_send(peer_addr, &data, sizeof(data)); // i want to send the data in uint8_t type*

  • Serial.print("Send Status: ");*

  • if (result == ESP_OK) {*

  • Serial.println("Success");*

  • }*

  • }*
    }
    i want to use :
    sendData("hello");
    i receive an error:
    error: incompatible types in assignment of 'uint8_t* {aka unsigned char*}' to 'unsigned char
    can somebody repair my code please!!!!
    Thanks

2 
uint8_t data =( uint8_t*)datos;

You assigned pointer into normal variable. Sholuld be:

uint8_t data =*( uint8_t*)datos;