system
1
Hello!
I am trying to use an array as base to build a text which will be displayed on a 8x8 matrix.
byte a[8]={0x00,0x7c,0x44,0x44,0x7c,0x44,0x00,0x00};
byte b[8]={0x00,0x7c,0x44,0x78,0x44,0x7c,0x00,0x00};
byte c[8]={0x00,0x7c,0x40,0x40,0x40,0x7c,0x00,0x00};
..
..
..
now.. instead of doing loops for each character I would like to put the displayed text inside another array, like this.
char text[7]={'a','r','d','u','i','n','o'};
how can I do the loop like this:
text[1][1] = 0x7c
text[2][3] = 0x44
I hope you know what I mean...
Thanks for any help!
-andreas
Do you mean like
char text[4][7]={
{'a','r','d','u','i','n','o'},
{'b','a','r','d','a','l','i'},
{'c','a','r','d','a','l','i'},
{'y','a','d', 'd','a','l','i'},
};
?
system
3
nope not really...
array#2 should trigger array#1
text[1] = "a";
and this "a" should be
a[2] = 0x7c;
You mean an array of pointers as a lookup table?
byte a[8]={0x00,0x7c,0x44,0x44,0x7c,0x44,0x00,0x00};
byte b[8]={0x00,0x7c,0x44,0x78,0x44,0x7c,0x00,0x00};
..
..
byte* chargen[] = {a, b...};
..
..
system
5
ehrmm... i should be more precise (my english is not the best since I am a native german speaker) 
more like this:
byte a[8]={0x00,0x7c,0x44,0x44,0x7c,0x44,0x00,0x00};
byte b[8]={0x00,0x7c,0x44,0x78,0x44,0x7c,0x00,0x00};
byte c[8]={0x00,0x7c,0x40,0x40,0x40,0x7c,0x00,0x00};
char text[] = {"a","b","c"};
loop pos[1-3] {
loop char[1-8] {
display text[pos][char]
}
}
I hope it's clear now..
-andreas
byte a[8]={0x00,0x7c,0x44,0x44,0x7c,0x44,0x00,0x00};
byte b[8]={0x00,0x7c,0x44,0x78,0x44,0x7c,0x00,0x00};
..
..
byte* chargen[] = {a, b...};
char text [] = {'a', 'b', 'c'};
for (int i = 0; i < sizeof (text); i++) {
byte* charArray = chargen [text [i] - 'a'];
for (int j = 0; j < 8; j++) {
byte pattern = charArray [j];
// send pattern to LCD
}
}
system
7
Groove... you're a genious! You saved my evening!
Big Up from Switzerland!
-andreas
Or you could just have it:
byte chargen [][8] = {
{0x00,0x7c,0x44,0x44,0x7c,0x44,0x00,0x00},
{0x00,0x7c,0x44,0x78,0x44,0x7c,0x00,0x00},
....
};
char text [] = {'a', 'b', 'c'};
for (int i = 0; i < sizeof (text); i++) {
for (int j = 0; j < 8; j++) {
byte pattern = chargen [text[i] - 'a'] [j];
// send pattern to LCD
}
}
or any number of variations!
have fun, enjoy!