Problems sending data with two eb301 bluetooth modules and two arduinos

Using Arduino Networking, Protocols, and Devices
#1

I apologize ahead of time if i’m posting in the wrong place or if this has already been discussed. This is my first post.

ok, so i have two arduinos with an eb301 bluetooth module attached to each. one arduino has a joystick connected to pins A0 and A1 and it seems to be working right. i see the values change in the serial port and i can connect it to my pc via bluetooth and also see the values change in putty. but on my receiver arduino with the two servos attached, i cant get them to move. the bluetooth modules seem to be paired but what should i change in my code to get it to read the values coming from arduino 1.
here are the codes im using:

Joystick transmitter: arduino 1

int potpin1 = 0;
int potpin2 = 1;

int newval1, oldval1;
int newval2, oldval2;

void setup() 
{
  Serial.begin(9600); 
}

void loop() 
{ 
  newval1 = analogRead(potpin1);           
  newval1 = map(newval1, 0, 1023, 0, 179); 
  if (newval1 < (oldval1-2) || newval1 > (oldval1+2)){ 
    Serial.println(newval1);
    oldval1=newval1;
  }
  
  newval2 = analogRead(potpin2);
  newval2 = map(newval2, 0, 1023, 0, 179);
  if (newval2 < (oldval2-2) || newval2 > (oldval2+2)){    
    Serial.println(newval2);
    oldval2=newval2;
  }
  delay(50);
}

Joystick receiver: Arduino 2

#include <SoftwareServo.h>  
SoftwareServo myservo1;
SoftwareServo myservo2;

int newval1, oldval1;
int newval2, oldval2;

void setup() 
{
  Serial.begin(9600);  
  myservo1.attach(12);  
  myservo2.attach(13);
}

void loop() 
{ 
  if( Serial.available() )       
  {;}
  newval1 = Serial.read();            
  newval1 = map(newval1, 0, 1023, 0, 179); 
  if (newval1 < (oldval1-2) || newval1 > (oldval1+2)){  
    myservo1.write(newval1);
    oldval1=newval1;
  }

  newval2 = Serial.read();
  newval2 = map(newval2, 0, 1023, 0, 179);
  if (newval2 < (oldval2-2) || newval2 > (oldval2+2)){  
    myservo2.write(newval2);
    oldval2=newval2;
  }
  delay(50);
}

Thank you in advance for any replies and help

#2