I would like to ask you, how does the capacitor current graph looks, if I apply a square wave signal(from 0 to 5Volts) into a RC circuit?,let’s consider a duty cycle of 50%?.

Thanks in advance for you response.

I think this is not the best section for that question, but:

It will be something like this: The capacitor will change the edges of the waveform. The rising edge will have a parabolic form, and so will the falling edge. The combined values of the components you mentioned will define the steepness of those flanks.

i=C (dv/dt)

Looks like this:-

zaciatok: I would like to ask you, how does the capacitor current graph looks, if I apply a square wave signal(from 0 to 5Volts) into a RC circuit?,let's consider a duty cycle of 50%?. Thanks in advance for you response.

RC or CR, one is low pass filter configuration the other is called something else, differenator ?

differenator ?

Yes.