The onboard LDO drops <= 1volt. So you could feed +6volt directly into Vin.
Not into the DC socket, because that drops another 0.6volt because of a polarity protection diode.
A cheap solution would be two (1N4004) diodes in series to drop 1-1.2volt.
Provided the 6volt supply is stable and clean.
Leo..
Had a look at the datsheet of a typical onboard 1117 LDO. Drop is ~1volt at ~300mA. And ~0.8v at a typical 100mA.
And yes, 1.2volt when you want to draw 500mA at 20degrees below zero.
Two diodes works fine. Arduinos also run on drooping USB supplies.
If 1.4v is too much, a 1N4004 and a 1N5819 (schottky) in series will drop 1.1volt @100mA (measured!).
Supply is not that critical, unless you want to measure analogue things accurately.
This Pololu buck converter is another option.
Dropout is 0.25volt at 200mA.
Leo..
Delta_G:
But they generally need a 110VAC outlet, and this I do not have. I only have 6VDC available.
I think I will just find an LDO regulator.
I'm with you on the LDO, but keep in mind that if you are making a bare circuit in the end and using an ATMega328P, it is speced from 1.8V-5.5V. You have a big voltage window to play in, depending on what other circuits you are going to interface to it (note you will have to use a slower crystal as you get closer to the lowest voltages). Arduino runs it at 5V only because some decision had to be made and that is the hobbyist voltage of choice
My arduino has an ethernet shield attached, and is powered from my netbook. The voltage on the arduino 5v pin is 4.32v. I've also seen the arduino operate for a short time with~8v indicating on the 5v pin. This is an old Duemilanove which appears to be fairly rugged.
That is what prompted me to see what was going on. I had a 12v battery connected to the external power jack at the time. Some issue with the on board voltage regulating system (9v connected resulted in ~7v). I then connected the 12v to an 7805 regulating chip connected to the 5v pin and everything was back to 5v.