And if I have an always current flowing though the voltage divider and the analog input, what do you think, how much current is drawn?
Additionally, I am interested in the way of how to calculate the current drawn and the estimated life using what the battery says about its mAh ...
So, assuming R3=10K, R4=1K. Higher resistor values decrease the current drawn, AFAIK.
Battery full = 9V, i.e. 9V*1K/(10K+1K)=9V/11 =0.8V (analogRead = 164)
But how to calculate the current drawn ??