Reconcile Analog

Projects Programming
45

Here's UKHeliBob's solution without for loops:

int translatePins(int pinNum)
{
  if (14 <= pinNum && pinNum < 20)
  {
    return pin - 14;
  }
  if (54 <= pinNum && pinNum < 70)
  {
    return pin - 54;
  }
  return -1;
}

Personally I would use the "A0" constant to make it a little clearer what it's doing:

int translatePins(int pinNum)
{
  if (A0 <= pinNum && pinNum < A0 + 16)
  {
    return pin - A0;
  }
  return -1;
}

(On the Uno, this version will convert pinNum 20 through 29 to the values 6 through 15, even though those pins don't exist.)