RegExp insert character instead of replace

Using Arduino Programming Questions
1

Hi,

I am trying to use the Regexp.h library by Nick Gammon to parse a string of text.
It comes in as V0417 R0393 G0432 B1014, using the library I was able to strip out everything I needed.
So now it comes out as 0393 0432 1014.

The only thing I cant figure out is how to add a period after the first character.
like this 0.393 0.432 1.014
In practice, all of the numbers will change but will always come in as 4 sets of 4 (I striped out the first set).

Any idea on how to just add the period after the first digit instead of replacing?

Thanks!

#include <Regexp.h>

void setup ()
{
  Serial.begin (9600);

  // what we are searching
  char buf [100] = "V0417 R0393 G0432 B1014";

  // for matching regular expressions
  MatchState ms (buf);

  // replace vowels
  ms.GlobalReplace ("V....", "");
  ms.GlobalReplace ("R", "");
  ms.GlobalReplace ("G", "");
  ms.GlobalReplace ("B", "");
  ms.GlobalReplace ("[.-...]", ".");


  Serial.println (buf);

}  // end of setup

void loop () {}
2

Just keep the R,G,B and swap out the indices. Then replace them with a dot.

char* SwapDots(char* buf)
{
    buf[0] = buf[1];
    buf[1] = '.';

    buf[6] = buf[7];
    buf[7] = '.';

    buf[12] = buf[13];
    buf[13] = '.';
    return buf;
}

void setup() {
  // put your setup code here, to run once:
    char buf[100] = "R0393 G0432 B1014";
    Serial.println(SwapDots(buf));
}
3

Thanks that’s perfect!

Thanks so much for the help!!

4

Turns out im an idiot and was using the a dump from a terminal to determine the proper string.
I was off.

This is the incoming string V0417 R0393 G0432 B1014
and this is what I need to turn it into V0.417 R0.393 G0.432 B1.014.

I am trying to use the code you sent to do that but its replacing instead of adding.
Any tips?

Thanks again!

5

Do you still need the letters in the final buffer? The method I provided tried to not shifting the buffer because it is complicated.

If you still want the letters. Replace it with itself and a space:

ms.GlobalReplace ("R", "R ");

Then use the SwapDots() to swap and replace the space with a dot. Note that you have to change the indices.

6

Thanks so much for the tip! I think I got it working.