Remember you're a button

Projects Programming
1

Hi,

Just having some small confusion, about how to turn an LED on with one button press and when you press the button again; turns the led off.

Instead of lighting up when held down. Surely it's something very simple!

Sorry for the extremely basic question!

2

Do a search for "debouncing button" to get on your way.

3

Thank you very very much!! :slight_smile:

4

This sketch is maybe want you want, every time you push a button a LED wil turn on, and next time you push itthe LED will turn off.

There is no debouncing , and there should be

int vent=100;
const int buttonPin = 7;
int flag=0;
int buttonState = 0;

void setup()
{
pinMode(4, OUTPUT);
pinMode(5, OUTPUT);
pinMode(buttonPin, INPUT);
Serial.begin(9600);
}

void loop()
{
// digitalWrite(4, HIGH);

buttonState = digitalRead(buttonPin);
delay(vent);

Serial.print(buttonState);
Serial.println();

if (buttonState==HIGH){

if (flag==1) {
flag=0;
}
else
{
flag=1;
}

}

if (flag==1){
Serial.print("HIGH\n");
digitalWrite(4, HIGH);

}

if (flag==0){

digitalWrite(4, LOW);

Serial.print("LOW\n");
}

}

5

I wrote it in an easy way..
Hope this helps you.. :slight_smile:

int button_pin = 11;
int led_pin = 13;
int button_state = 0;
int led_state = LOW;

void setup(){
  pinMode(button_pin, INPUT);
  pinMode(led_pin, OUTPUT);
}

void loop(){
  if(button_state == HIGH){
    led_state = !led_state;
    digitalWrite(13, led_state);
    delay(100);
  }
}
6

Cheers for the response, really good looking code, but couldn't get the LED to come on!

7

Joy:
I wrote it in an easy way..
Hope this helps you.. :slight_smile:

Enjoy your rapidly blinking LED. That will, as long as the button is pressed, toggle the LED every 100ms.