Reverse Data

How can I reverse HEX data Exp {35 45 6D} to {6D 45 35}? Thank you

You could start by posting your code and a fuller description of the problem.

Briefly, copy from source array while incrementing index and store in destn array while decrementing index.

Adipong_Saengsuk:
How can I reverse HEX data Exp {35 45 6D} to {6D 45 35}? Thank you

dougp:
Briefly, copy from source array while incrementing index and store in destn array while decrementing index.

void setup()
{
  Serial.begin(9600);
  byte srcArray[] = {0x35, 0x45, 0x6D};
  byte dstArray[3];

  for(int srcIndex = 2, dstIndex = 0; srcIndex>=0, dstIndex<=2; srcIndex--, dstIndex++)
  {
    dstArray[dstIndex] = srcArray[srcIndex];
    Serial.print(dstArray[dstIndex], HEX);
    Serial.print(" ");
  }
}

void loop()
{

}

reverse HEX data Exp {35 45 6D} to {6D 45 35}

byte temp;
temp = data[2];
data[2] = data[0];
data[0] = temp;

Or something more generic that will work with any size array:

for (byte i = 0; i < (arraysize / 2); i++) {
    temp = test[i];
    test[i] = test[(arraysize - 1) - i];
    test[(arraysize - 1) - i] = temp;
  }
// Example of inverting elements in an array
int test[25];
int temp;
byte arraysize = sizeof(test) / sizeof(test[0]);

void setup() {
  Serial.begin(9600);
  for (byte i = 0; i < arraysize; i++) { //fill array with sequential numbers
    test[i] = i;
  }
  for (byte i = 0; i < arraysize; i++) { //print array contents
    Serial.print("Test[");
    Serial.print(i);
    Serial.print("]=");
    Serial.println(test[i]);
  }
  Serial.println();
  delay(5000);
}

void loop() {
  for (byte i = 0; i < (arraysize / 2); i++) {
    Serial.print("swapping elements ");
    Serial.print(i); Serial.print(" <> ");
    Serial.println(arraysize - 1 - i);
    temp = test[i];
    test[i] = test[(arraysize - 1) - i];
    test[(arraysize - 1) - i] = temp;
  }
  Serial.println("");
  for (byte i = 0; i < arraysize; i++) { //print array contents
    Serial.print("Test[");
    Serial.print(i);
    Serial.print("]=");
    Serial.println(test[i]);
  }
  Serial.println();
  delay(30000);
}

Five answers to an XY problem?