Safe values in File.txt - Help-me please

Forum 2005-2010 (read only) Software Syntax & Programs
1

How do I save the values of my sensor in a file?
I have a parallax ping sensor, and would like to save the values in a file. To work the movement of objects on the screen, such as circles, lines and squares.
I'm using the right reading? I confess I'm confused. I have to use byte or string?
Does anyone have a better idea?

my code:

import processing.serial.*;

Serial myPort;

void setup() {
println(Serial.list());
myPort = new Serial(this, Serial.list()[0], 9600);
}

void draw() {
// Expand array size to the number of bytes you expect
byte[] inBuffer = new byte[7];
while (myPort.available() > 0) {
inBuffer = myPort.readBytes();
myPort.readBytes(inBuffer);
if (inBuffer != null) {
String myString = new String(inBuffer);
//println(myString);
createOutput(myString="/home/samuel/sketchbook/distan.txt");
}

}
}

2

What does the arduino code look like?

You are reading the data into processing, is that how you plan to do the graphics?

Why do you need the file storage?

3

Well, I do not have much practice with processing. I planned to use the values obtained by Arduino + parallax ping sensor to draw lines on the monitor according to the distance from my hand to the sensor. But I have no idea how to use these values, so I store them in text file. It could even generate circles according to the distance. Example: if I position the hand in the middle of the monitor, right there for the right to draw lines.

Example:
Youtube have one example for my idea

my code arduíno used ping parallax sensor

const int pingPin = 7;

void setup() {

Serial.begin(9600);
}

void loop()
{
long duration, inches, cm;

pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
digitalWrite(pingPin, LOW);

pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);

cm = microsecondsToCentimeters(duration);

Serial.print(cm);
Serial.print("cm");
Serial.println();

delay(100);
}
long microsecondsToCentimeters(long microseconds)
{
return microseconds / 29 / 2;
}

thanks for help-me