Hi all, I would like to check I am doing something right. I am routing a PCB that will use a GPS antenna, and I need to use a 50 Ohm trace to connect the antenna. I am going to get it made as a two layer, 1.6mm, 1Oz copper board from JLC PCB. I have used an online calculator and it says I need a 2.7mm trace width to get an impedance of 50 Ohms?! Seems way to wide to me, am I doing something wrong? Here are some links:
I used the OSHpark 2 layer board info page to find the "PCB Substrate dielectric constant". It says it is 4.6 at 1MHz. I know it changes with frequency and JLC PCB will probably use a different substarte with a different value, but I just want a rough idea, doesn't have to be prefect. For the dielectric thickness, I used 1.5mm since that is the distance between the top and bottom copper for a 1.6mm board from JLC PCB.
Does 2.7mm seem correct for this? Or am I doing something stupid? Thanks in advance!