I've been busy the past few days but I'm wondering if this would work. make 2 new arrays called tempLat and tempLong
tempLat[10] //0-9 for the lat digits, 10 for null
tempLong[11] //0-10 for the long digits, 11 for null
for (int i=0;i<12;i++){
switch(i){
case 0 :Serial.print("Time in UTC (HhMmSs): ");break;
case 1 :Serial.print("Status (A=OK,V=KO): ");break;
case 2 :Serial.print("Latitude: ");break;
case 3 :Serial.print("Direction (N/S): ");break;
case 4 :Serial.print("Longitude: ");break;
case 5 :Serial.print("Direction (E/W): ");break;
case 6 :Serial.print("Velocity in knots: ");break;
case 7 :Serial.print("Heading in degrees: ");break;
case 8 :Serial.print("Date UTC (DdMmAa): ");break;
case 9 :Serial.print("Magnetic degrees: ");break;
case 10 :Serial.print("(E/W): ");break;
case 11 :Serial.print("Mode: ");break;
case 12 :Serial.print("Checksum: ");break;
}
for (int j=indices[i];j<(indices[i+1]-1);j++){
int n=0;
int m=0;
Serial.print(linea[j+1]);
if (i == 2)
{
tempLat[n] = linea[j+1];
n++;
}
if (i == 4)
{
tempLong[m] = linea[j+1];
m++;
}
}
now what about that code? I know n=0 and m=0 there is dumb but thats just to show the variables. In actuality I would set them to 0 at the beginning of the loop function. However, I think this would store the latitude and longitude each as their own array of chars. Then I could atoi each array right? and then I'd have each array stored into an int?
Also, these numbers are going to have 4 decimal places, so I have to use floats? so I'd use atof instead of atoi?