and yes at the least it should go to an alternate site or shorten the time before retrying.
Retrying? Your sketch runs exactly once and will never retry, even not in the case of an error.
Another problem (from the view of the service provider): You're opening a keep-alive connection but you're not closing it but wait for a timeout on the server side. This way you're wasting resources. For what you're doing an HTTP/1.0 connection is enough and there the keep-alive option should be ignored anyway but nevertheless you should not send it.
Where do you have the IP from? If it's fixed you wouldn't need the service so it must be dynamically assigned but you wrote it directly into a constant string.
You should store the constant strings into program memory and use the F() macro for all print() and println() calls. This saves you RAM that you may need otherwise.