Hi, i try to create a sequence with a button sequence and a lock.
I found a way to do it with multiple buttons and a sequence (eg. 1-2-3-4), but i want the sequence to be three times the same button. The relay needs to release the latch for 10 seconds, then goes back to lock position.
The sequence may take 25 seconds to complete.
Can someone help me? (sorry for my english, it is not my first language!
Thank you.
Is it possible to start with this code:
int key = 0;
int Solved = 0;
int count = 2;
char code[8] = "ttabcd"; //first 2 chars are space holders only
int keyCounter[6] = {0, 0, 0, 0} ; // Set key flag
void setup() {
pinMode(8, OUTPUT);
pinMode(9, OUTPUT);
pinMode(13, OUTPUT);
for (int i = 2; i <= 6; i++)
{
pinMode(i, INPUT); // for D2 and up
}
}
void loop()
{
if (Solved == 0)
{
while (count != 6)
{
for (int i = 2; i <= 6; i++)
{
key = digitalRead(i);
delay(40);
if (key == LOW && keyCounter[i] == 1) {
keyCounter[i] = 0;
break;
}
if (key == HIGH && keyCounter[i] == 0)
{
digitalWrite(8, HIGH);
delay(20);
digitalWrite(8, LOW);
delay(330);
switch (i)
{
case 1:
if (count == 2 && code[i] == 'a')
{
count = count + 1;
}
else
{
count = 2;
}
keyCounter[i] = 1;
break;
case 2:
if (count == 3 && code[i] == 'c')
{
count = count + 1;
}
else
{
count = 2;
}
keyCounter[i] = 1;
break;
case 3:
if (count == 4 && code[i] == 'c')
{
count = count + 1;
}
else
{
count = 2;
}
keyCounter[i] = 1;
break;
case 4:
if (count == 5 && code[i] == 'b')
{
count = count + 1;
}
else
{
count = 2;
}
keyCounter[i] = 1;
break;
}
}
}
}
}
if (count == 6)
{
digitalWrite(9, HIGH);
count = 2;
delay(1000);
digitalWrite(9, LOW);
Solved = 0;
}
else
{
Solved = 0;
}
}
