Serial.begin problem

Using Arduino Programming Questions
1

First off, I'm sorry I'm so new. This is probably something so simple.

I've just learned about Serial.begin and I've added into my void setup when I'm simply making two LED's blink. They work fine but when I add the Serial.begin(9600); at the top of void setup it now makes my first LED stay on constantly while the other works as programmed.

int redLED=1; // Red LED set to 1
int yellowLED=3; // Yellow LED set to 3
int redOnTime=1000; // Red LED On Time
int redOffTime=1000; // Red LED Off Time
int yellowOnTime=1000; // Yellow LED On Time
int yellowOffTime=500; // Yellow LED Off Time
int numRedBlink=3; // number of times blink red
int numYellowBlink=3; //number of times blink yellow

void setup() {
Serial.begin(9600);

pinMode(redLED, OUTPUT);
pinMode(yellowLED, OUTPUT);

}

void loop() {

Serial.println("The Red LED is Blinking!");

for (int j=1; j<=numRedBlink; j=j+1 ) {
Serial.println(j);
digitalWrite(redLED, HIGH); // Turn red LED on
delay(redOnTime);
digitalWrite(redLED, LOW); // Turn red LED off
delay(redOffTime);

}
Serial.println(" ");
for (int j=1; j<=numYellowBlink; j=j+1){
digitalWrite(yellowLED, HIGH); // Turn yellow LED on
delay(yellowOnTime); // Wait
digitalWrite(yellowLED, LOW); // Turn yellow LED off
delay(yellowOffTime); // Wait
}

}

2

serial uses pins 0 and 1.

Move the leds to different pins and your code should work ok

3

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4

gpop1:
serial uses pins 0 and 1.

Move the leds to different pins and your code should work ok

Thanks for your help. You were right. I'm using pins 3 & 6.