Serial Monitor, CC1101

Projects Programming
1

Hello,i am using two rf modules cc1101 and i am having a problem on the receiving end.

This is my code for transmitting.

#include <ELECHOUSE_CC1101.h>

void setup() 
{
   Serial.begin(9600);
   ELECHOUSE_cc1101.Init();
}

void loop() 
{
   delay(500);
   
   String locat = "+03 Electrical Engineers";
   int locat_length = locat.length();
   byte locat_byte[locat_length];
   locat.getBytes(locat_byte, locat_length + 1);  
   Serial.println((char *)locat_byte);  
   ELECHOUSE_cc1101.SendData(locat_byte, locat_length);
}

This is my code for receiving.

#include <ELECHOUSE_CC1101.h>
String locat;
int StDir=0;
byte buffer[100] = {0};
void setup() 
{ 
   Serial.begin(9600);      // the Serial port of Arduino baud rate.
    
   
   ELECHOUSE_cc1101.Init();
   ELECHOUSE_cc1101.SetReceive();    
}
void loop()
{
   if (StDir == 0)
   {  
      if (ELECHOUSE_cc1101.CheckReceiveFlag()) 
      {               
         ELECHOUSE_cc1101.ReceiveData(buffer);
         
         String str((char*) buffer);
         Serial.println(str); //Μηνυμα πομπου
         
         locat=str.substring(4);
         Serial.println(locat); //Ονομα περιοχης
         
         StDir=str.substring(0,3).toInt();
         Serial.println(StDir); //Κατευθυνση οχηματος
         
         String Entry = locat; //Διευθυνση εισοδου
         //Αποθηκευση του Entry στην SD
      }
      Serial.println("Waiting to enter the Highway");
      delay(5000);       
   }
   else
   {
      GPS();
   }      
}

The problem is that in serial monitor i don't get the message from the tranmitter and it only shows
Waiting to enter the Highway
But when i delete this lines of code

Serial.println("Waiting to enter the Highway");
      delay(5000);

i get the message from the transmitter and it gets shown in the serial monitor.
I cannot figure out why this lines of code block my messages.

Thanks in advance

2

I cannot figure out why this lines of code block my messages.

You can't? What happens when delay() is running? NOTHING! No radio reception.

3

PaulS:
You can't? What happens when delay() is running? NOTHING! No radio reception.

Even if i delete delay(), i don't get the message from the transmitter. I have to delete both lines of code to get the message

4

I have to delete both lines of code to get the message

The problem is probably in the code you didn't post.

5

Dit you got solved the Problem?

And how?