Servo Motor + LED Question.

Projects Programming
1

I have a question concerning a project I've been working on. I have a Servo motor starting at angle 0 then delaying one second and going to angle 160, delaying one second and going back to 0. What I want to do is once it reaches 160 degrees to turn on a LED. And when it goes back down to 0, turn off the led. This is what I have so far.

#include <Servo.h>

Servo myServo;
int led = 3;

int pos = 0;

void setup()
{
myServo.attach(9);
pinMode(3, OUTPUT);

}
void loop()
{

digitalWrite(3, HIGH);
myServo.write(0);
delay(1000);
myServo.write(160);
delay(1000);
myServo.write(0);
delay(1000);

}

--

Any help would be appreciated.

2

Did you connect a led with resistor to pin 3 ?
Turn led on: digitalWrite(3, HIGH);
Turn ledd off: digitalWrite(3, LOW);

3

Yes. A 220-ohm resistor is connected and it works just fine. I just need to know the code to turn it on and off based on the angle of the motor.

4

After you set the angle to 160 degrees (and before the delay) turn the led on.
And after you set the angle back to 0 degrees, turn the led off.
Can you do that ? Give it a try.
You can copy-paste your sketch between code tags, use the '#'-button (above the text field when you type a reply).

5

I am not good at programming, but hope this works :::

#include <Servo.h>

Servo myServo; 
int led = 3;

int pos = 0;

void setup()
{
  myServo.attach(9);
  pinMode(3, OUTPUT);
  
}
void loop()
{
  myServo.write(0);
  delay(1000);
  myServo.write(160);
 digitalWrite(led, HIGH);
  delay(1000);
  myServo.write(0);
  digitalWrite(led, LOW);
  delay(1000); 

}

If the led lights up before completing the rotation, note the time it takes to complete the rotation and add that much delay before digital writing led.
Please copy-paste your sketch between code tags, use the '#'-button (above the text field when you type a reply).

6

To synchronize the code to the rotation you'll need to step the servo a bit at a time, or
to estimate the seek-time of the servo.

So stepping in synch:

  for (int i = 0 ; i <= 160 ; i++)
  {
    servo.write (i) ;
    delay (2) ;
  }
  digitalWrite (LED, HIGH) ;
  delay (1000) ;
  for (int i = 160 ; i >= 0 ; i--)
  {
    servo.write (i) ;
    delay (2) ;
  }
  digitalWrite (LED, LOW) ;
  delay (1000) ;

or estimating:

  servo.write (160) ;
  delay (200) ;
  digitalWrite (LED, HIGH) ;
  delay (1000) ;
  servo.write (0) ;
  delay (200) ;
  digitalWrite (LED, LOW) ;
  delay (1000) ;
7

Frenzy654 and MarkT answered my question, thank you.