I am working on my arduino robot arm. Its made out of 5 servos. And I have a problem with a power supply. I found a DC power converter. The output voltage is around 12V DC and output current is 5.8A. But my servos work on 5V and I don t know how to lower voltage to 5V without lossing to much of current. I tried with ressistors but there isn t enough current and
the servos don t work. Do you have any ideas how to lower voltage more efficiently?
To do so, to source a bunch of parts and so on, will likely cost more than just buying a suitably rated supply.
http://www.jameco.com/ has lots of power supplies.
Thanks for you answers! You are probbably right, but can you just tell me how to do it? Because I would really like to know how to do it.
Using a buck regulator is a simple thing.
Trying to keep the 5A is not so simple a thing. Is that important?
You could use a few linear regulators (7805), dividing the servos among them; 5V_a for servos 1, 2, 5V_b for servos 3, 4 and 5V_c for servo 5. Something like that.
It's a matter of time and money.
I never thought about connecting more regulators. And I think it might work, because only the first servo draws 1A of current, other servos use 200 - 500 mA. I will try it on breadbord and see if it will work.
Thanks for your help
my servos work on 5V and I don t know how to lower voltage to 5V without lossing to much of current.
What kind of servos are you using that use only 5v?
I presume standard servos rated 4.8V to 6V (or 7.2V) supply are what is meant! None of them work at 12V.
The best way to drop the voltage is with a DC-DC converter - finding a cheap one rated at over 1A is a bit of an issue, but fortunately these adjustable LM2596 modules are readily available on eBay:
I presume standard servos rated 4.8V to 6V (or 7.2V) supply are what is meant!
Well, only the OP can answer that question. If the servos are the typical 4.8v to 6v hobby types, then at only 5v the arm might not even be able to lift itself. High current 6v UBECs like below are made for powering servos. Also a 7805 regulator chip can be used with a diode to increasethe chip’s output to ~5.7v.