Sharp GP2Y0D02 (Digital output)

Other Hardware Sensors
1

Hi!
I need help with Sharp GP2Y0D02 (Digital output) sensor.
I've already used the analog sensor with success but for a particular project I need the digital version that outputs an HIGH voltage if an obstacle stays in the range of 80cm in front of the sensor.

I thought it was easy reading this sensor but I can't.

Maybe I need help with connection because I wired directly the sensor output to a digital pin as the 5V and ground. The datasheet speaks about a by-pass capacitor of 10μF and I see in the circuit a resistance of 12KΩ between Vo and Vcc...
I'm sorry but I'm not able to undestand what should I do..

Can you explain me better or post a tutorial where I can see what I have to do?

Thank you

PS
this is the simple code I used:

const int sensor = 2;
const int led = 13;

void setup() {

  pinMode(sensor, INPUT);
  pinMode (led, OUTPUT);

  Serial.begin(9600);
}

void loop() {

  int val = digitalRead(sensor);

  if(val == HIGH){
    digitalWrite(led, HIGH);
  } else {
    digitalWrite(led, LOW);
  }
  Serial.println(val);

  delay(500);
}
2

Depending on your circuit (you failed to post a wiring diagram) all you need to do to make this sensor work is changing this line

  pinMode(sensor, INPUT);

to

  pinMode(sensor, INPUT_PULLUP);
3

Perfect! Thank you!