Shiftout a byte

Projects Programming
1

Im defining my bytes like this:

byte digit[10][7]={{1,1,1,1,1,1,0},//0
                  {0,1,1,0,0,0,0},//1
                  {1,1,0,1,1,0,1},//2
                  {1,1,1,1,0,0,1},//3
                  {0,1,1,0,0,1,1},//4
                  {1,0,1,1,0,1,1},//5
                  {1,0,1,1,1,1,1},//6
                  {1,1,1,0,0,0,0},//7
                  {1,1,1,1,1,1,1},//8
                  {1,1,1,1,0,1,1}};//9

but this doesnt work:

shiftOut(dataPin, clockPin, MSBFIRST, digit[numb]);

How do i convert the bytes to an int?

2

You better use the individual bits in the byte

byte digit[10][7]={{1,1,1,1,1,1,0},//0
{0,1,1,0,0,0,0},//1
{1,1,0,1,1,0,1},//2
{1,1,1,1,0,0,1},//3
{0,1,1,0,0,1,1},//4
{1,0,1,1,0,1,1},//5
{1,0,1,1,1,1,1},//6
{1,1,1,0,0,0,0},//7
{1,1,1,1,1,1,1},//8
{1,1,1,1,0,1,1}};//9

becomes
byte digits[10] = { B01111110, B00110000, B01101101, B01111001, B00110011, B01011011 etc

Then the shift should work. (also take only 10 bytes of RAM iso 70)

succes,

3

thanks, that worked except i had to put the 0's at the end and change it to LSBFIRST... i guess just from how i wired it.