Simple maths question: Converting note to hertz

Hi,

I'm trying to convert midi notes to hertz. I didn't do very well in my maths GCSE, and my coding is remedial.

The equation I'm using is here:
modusponem.com/53/midi2hertz/

Frequency(MidiNote) = 2^((MidiNote-69)/12)*440

I'm using this code to check my maths is working - and it clearly isn't (it produces results that are rounded - showing to 2 decimal places. Note 69 is 440, which is correct, but lots of other notes are also 440, which is incorrect.)

Thank you!

Tom

void setup() {
  Serial.begin(9600);
}

int note;
float hz; 


void loop() {
  
  for (note = 0; note <255; note++){
  
  hz = pow (2.0, ((note-69)/12));
  
  Serial.print("note = ");
  Serial.print (note);
  Serial.print ("  hertz =");
  Serial.println(hz*440, DEC);
  delay(100);
  }
  
}
hz = pow (2.0, ((float)(note-69)/12.0));

Maybe?
Reason being, (note-69)/12 for values of "note" up to 81, the value of the division will be zero (integer-only arithmetic).

That's the job, works perfectly. Thank you!