Simple Shift Reg.(595) Question...?

Projects Programming
1

The following code sends 5V to Q7 as desired. But the problem is that it stays High, how can I make it stay on for just n seconds only?

thanks

void loop() {
    digitalWrite(latchPin, LOW);
    shiftOut(dataPin, clockPin, LSBFIRST, 1);
    digitalWrite(latchPin, HIGH);
    delay(3000);
}
2

First write code to turn off the pin and test it. Then see this tutorial ..

This will show you a good way to have something happen for x period of time.

3

Well I tried the following of No avail!?

 void loop() {
    digitalWrite(latchPin, LOW);
    shiftOut(dataPin, clockPin, LSBFIRST, 1);
    digitalWrite(latchPin, HIGH);
    delay(3000);
  digitalWrite(latchPin, LOW);  
    shiftOut(dataPin, clockPin, LSBFIRST, 0);
    digitalWrite(latchPin, HIGH);
}

Wasn't that supposed to write Zero's to all the bits?
Isn't there a way of resetting the bits? I know pin 10 is Clear but don't know how to use it?

thanks for the help

4

Well my mistake! I should have added a " delay(3000);" after the last line of code. :blush: