The booting mechanism of 6800/6802 was very cryptic; even, today I think why did Motorola do like that way. In 8085, the processor straight hits at location 0000H to fetch the opcode of the first valid instruction.
In 6800/6802, the processor hits at location FFFE to get an 8-bit data (user-defined) and then it hits at location FFFF to get another 8-bit data (user-defined). The resultant 16-bit (I forgot which one is the upper byte) was loaded into PC and the execution began from the location pointed by PC.