Skipping a number in a counting code

Projects Programming
1

Hi All,

I am having trouble with my code for a counting program. I currently have this:

void setup() {
 
 Serial.begin(9600);
 Serial.println("Counting to 10");
 Count4Me(10);
 
}

void loop() {
 // put your main code here, to run repeatedly:

}

void Count4Me(int num) {
 int i = 1;

 while (i <= num) {
   Serial.println(i);
   i = i + 1;
 }
}

This counts to 10 and then stops, which is perfectly working. However, I now want to make it so that when it goes to count it skips or just doesn't print out a certain number on the monitor (for example the number 4).

I have been looking into the reference for the constrain() command and doing research into it, but I am pretty new to all this and still am not quite sure how it works, or whether I am even on the right track.

Help please!

Thanks in advance, Jack.

2 
void setup()
{

  Serial.begin(9600);
  Serial.println("Counting to 10");
  Count4Me(10);

}

void loop()
{
  // put your main code here, to run repeatedly:

}

void Count4Me(int num)
{
   for (byte i = 1; i <= num; i++)
  {
    if (i != 4)
    {
      Serial.println(i);
    }
  }
}

See ITEM #7

https://forum.arduino.cc/index.php?topic=148850.0

3

Wow, that works perfectly thanks heaps!

I have looked more into the if() command and the != statement and that makes a lot of sense actually.

Thanks for putting me on the right path!

4

Then, how about paying the forum back, and editing your code to use code tags, as requested in reply #1?

5

Done.

6

Since you pass the number to count up to as a parameter, perhaps you should do the same with the number you want to skip.

7

Another way to do it:

void Count4Me(int num)
{
   for (byte i = 1; i <= num; i++)
  {
    if (i == 4)
      continue;
   
   Serial.println(i);
  }
}

The 'continue' statement causes the sketch to skip to the next iteration of the loop.