(((SOLVED))) current supply for chips

usually when i use chips on the breadboard i supply a 5v regulated voltage with an intensity of current ranging from 800mA to 1A . for for each chip i put a capacitor between the VCC and GND pins and that's about it , and it usually works fine i never had a broken chip or anything .
but now i have this expensive chip , some wrong happening to it might cost me alot , and in the datasheet it says the maximum intensity current that can be supplied to it is 320mA .

so , can i continue working with it the same way i usually handle chips ? or what ?

What kind of chip is it ?

The rated current of 320mA could be the maximum consumption of the chip. In other words its the current that your power supply must be able to handle. In this case your 800mA power supply is adequate.

I suggest you post a link to the chip datasheet in order to get more help.

The current rating of a voltage supply is the maximum safe current that can be drawn from it.

A 5V, 500mA supply doesnt always give 500mA, thats the upper limit.

So a 5V 800mA/1A supply is safe to be used with a chip that needs 320mA maximum current.

amine2,

The relationship between voltage, current, and resistance is described by [u]Ohm's Law[/u]. Ohm's Law is the 1st thing you learn when you take an electronics class.

Resistance means the resistance to the flow of electrical current. With high resistance, less current flows. With low resistance, more current flows.

In general, the voltage is fixed (or controlled) and the current depends on the resistance.* They don't tell you the resistance for a chip, but the datasheet will give you the current. (With a chip, the actual current usually also depends on what's connected to it.)

At your wall socket there is either 120V or 240V and that's constant. The amount of current depends on what you plug in. If you plug-in too many things, too much current flows and you blow a breaker (and the voltage drops to zero).

You can use the water flow in a pipe analogy (NOT a perfect analogy**)...

  • Current is water flow
  • Voltage is water pressure. With higher pressure, more water flows.
  • High resistance is a skinny pipe and very little water flows. Low resistance is a fat pipe and water flows easily.

For example if you connect an LED (with an appropriate series resistor) to a "little" 12V power supply, you might get 20 milliamps (0.02 Amps). You can connect that same LED & resistor to a 12V car battery that's capable of 500 Amps and you'll get the same 20mA current.

Or, here's an "opposite" example... You can take a couple of regular 9V batteries and put them in series to get 18V. That's more voltage than a car battery, but if you try to start your car with that setup the batteries are only capable of around 1Amp (that's a guess) for a very short period of time before they die... I don't know what the resistance of a car starter, but it's much-much less than 1 Ohm. Ohm's Law is a law of nature and it's always true. So, when you try to apply 18V across your car's starter with 2 small 9V batteries, the voltage drops to almost zero and the starter doesn't move.

* Or impedance. Resistance and impedance are both measured in Ohms.

* The biggest problems with the water analogy are - If you cut a pipe, the resistance goes to (nearly) zero and water flows-out freely all over the place. If you cut a wire, the resistance goes to infinity and no current flows.

And with water, there's nothing wrong with low-resistance... Nothing bad happens with no water-resistance. If there's no electrical resistance, usually too much current flows, bad things happen and things burn-up.

Good explanation Doug. However, being a little pedantic in my old age, I would add that Ohm's law is only true for a linear device and not for a "chip".

Russell.

thank you very much guys :slight_smile: .
sorry for my ignorance i am mostly a programmer .
[SOLVED]

SOLVED as in you are no longer mostly a programmer?!