Someone can help with sprintf(); ?
I need seperate numbers and asign them to Variables.
int number = 123456;
void setup()
{
Serial.begin(9600);
}
void loop()
{
int buff[5];
sprintf(buff, "%.6u", testNumber);
int Variable[5];
Variable1 = buff[0];
Variable2 = buff[1];
Variable3 = buff[2];
Variable4 = buff[3];
Variable5 = buff[4];
Variable6 = buff[5];
Serial.println(Variable);
}
Can someone repair my code?
Variable can be integer
Actualy it is does not matter, I just would like that this code was work.
Xenon69:
Variable can be integerActualy it is does not matter, I just would like that this code was work.
Variable is an integer array.
Variable1, Variable2, Variable3, Variable4, Variable5 and Variable6 are undefined.
I think you meant to use Variable[0] through Variable[5] instead.
You can't write 6 characters and a terminating NULL in a 5 element array.
... The whole program is just one big error from start to finish...
Hello, let me link you to a similar topic: Arduino Forum 
But still, your idea of using sprintf could work, if you understand that an array of size 5 can hold 5 elements: 0, 1, 2, 3, 4. And, as said, the string must have enough room for (in your case) 7 characters: '1', '2', '3', '4', '5', '6', '\0'.
Another suggestion is just to simply map from character to integer. So the fix to your code is:
Variable[0] = buff[0] - '0';
Cheers!
So the fix to your code is:
That will work for '0' to '9', but fail rather miserably for 'A' to 'F'.
PaulS:
So the fix to your code is:
That will work for '0' to '9', but fail rather miserably for 'A' to 'F'.
True but using sprintf(buff, "%.6u", testNumber) should not include them? And yepp I know this is another problem with original code. After fixing the number format for sprintf we will need to get back to how to map character '0'..'9' and 'A'..'F' to number 0..15.
Small steps forward!