stay in the same value of analog input give output one time

Projects General Guidance
23

Here is the working code. NOTE: this is just a sample.

const int sensor[] = {A0,A1,A2}; //number of inputs
int flagged[] = {0,0,0}; //must correspond with # of inputs
int Num=0;
void check(int Num);

void setup ()
{
  Serial.begin (9600);
}

void loop ()
{
  for(Num = 0; Num<=2/* change with inputs*/; Num++)
  { 
    /*Serial.print("X: ");
     Serial.print(analogRead(sensor[0]));
     Serial.print("\t");
     Serial.print("Y: " );
     Serial.print(analogRead(sensor[1]));
     Serial.print("\t");
     Serial.print("Z: " );
     Serial.print(analogRead(sensor[2]));
     Serial.println();*/
    check(Num);
  }   
}

void check(int Num)
{
  if(analogRead(sensor[Num])==1023)//when variable resistance give value =1023 print 'x' 
  { 
    if(!flagged[Num] && Num == 0 /* change with inputs*/) 
    {
      Serial.print("x"); //do if condition is true
      Serial.println();
      flagged[Num] = 1;
    }

    if(!flagged[Num] &&  Num == 1) 
    {
      Serial.print("y");//do if condition is true
      Serial.println();
      flagged[Num] = 1;
    } 

    if(!flagged[Num] &&  Num == 2 ) 
    {
      Serial.print("z");//do if condition is true
      Serial.println();
      flagged[Num] = 1;   
    }
    delay (100);
  }
  else flagged[Num] = 0;
  return;
}