Storing a joystick input sequence

Projects Programming
1

So, I was trying to do a KONAMI sequence on a joystick to turn on a green led.
For those unaware, the sequence is UP UP DOWN DOWN LEFT RIGHT LEFT RIGHT.
I figured that I needed to store the sequence in an array, then compare it with the sequence of the input. But I don't know how. For now, I wrote this:

'

const int JX = A0;
const int JY = A1;
const int JB = 2;

const int RED = 4;
const int GREEN = 5;

int POS;
int Pos16;
int Pos15;
int Pos14;
int Pos13;
int Pos12;
int Pos11;
int Pos10;
int Pos9;
int Pos8;
int Pos7;
int Pos6;
int Pos5;
int Pos4;
int Pos3;
int Pos2;
int Pos1;
int Combo;
int PrevPos;
int FinPos;
int StoredPos;

void setup() {
 Serial.begin(9600);
 pinMode(JB, INPUT);
 pinMode(RED, OUTPUT);
 pinMode(GREEN, OUTPUT);

}

void loop() { 

 int x = analogRead(JX);
 int y = analogRead(JY);
 int b = digitalRead(JB);

  PrevPos=POS;

if(x == 1023 && y != 0 && y != 1023){ 
  POS = 1; 
} else if(x == 0 && y != 0 && y != 1023){ 
  POS = 2; 
} else if(y == 0 && x != 0 && x != 1023){ 
  POS = 3; 
} else if(y == 1023 && x != 0 && x != 1023){ 
  POS = 4; 
} else {
  POS = 0;
}

if(PrevPos != POS){
  FinPos = PrevPos;
} else {
  FinPos = 0;
}

 Serial.println("X: " + String(x)+",\tY: " + String(y)+",\tP: " + String(b)+",\tPOS: " + String(POS)+",\tPREVPOS:"+ String(PrevPos)+",\tFINPOS:"+ String(FinPos));
 delay(100);

}

How do I store the FinPos in an array?

2

First declare the array

int finPos[16];    //an array of 16 integers

Declare a variable to be used as an index to the array

byte currentIndex = 0;  //start the index at zero

Each time you want to save a value

finPos[currentIndex] = currentValue;  //save the current value to the current level in the array
currentIndex++;  //move to next level of the array

When the value of currentIndex equals 16 then 16 values have been saved

3

... equals 15 (0...15) then 16 values...

UP UP DOWN DOWN LEFT RIGHT LEFT RIGHT B A SELECT

4

It depends where you test the value. To me the obvious place is immediately after incrementing it, hence

I agree that I could have been more specific, but my aim was to get @spacecipolla to think for themselves instead of providing a potted answer