"struct name" does not name a type ESP32

Using Arduino Programming Questions
1

hi im getting this error message, tried to look after solutions in this forum but none of them worked.I am declaring this gpio pins as the example sketch (GPIO/GPIO interrupt) in the IDE. i am working with an ESP32 devkit. all the code below is outside and before any functions(setup(), loop() etc.
code:

//GPIO declarations.
struct GPIO {
  const uint8_t PIN; // gpio pin assingment
  uint32_t timesAct;// how many times it has been triggered.
  bool state; //stores state.
};

GPIO btn1 = {34,0,false};
GPIO btn2 = {35,0,false};
GPIO btn3 = {32,0,false};
GPIO btn4 = {33,0,false};
GPIO ledW = {13,0,false};
GPIO ledG = {12,0,false};
GPIO ledY = {14,0,false};
GPIO ledR = {27,0,false};
2

GPIO is likely a define or something used by the core environment
➜ Change GPIO into tGPIO And it should work

1 Like
3

it worked thank you. 4 years into this, programming on avr, arduino, idf and pic and didn't realize something like that :slight_smile:
have a good weekend

4

Have fun!

1 Like
5

We don't see your error message!

6

We did, it’s in the title, and it’s solved.

7

When OP is saying -
"hi im getting this error message [...].", I am expecting to see the following error message that has been reported in the IDE.

test-1:17:1: error: 'GPIO' does not name a type
 GPIO btn1 = {34, 0, false};
 ^~~~

Traditionally, GPIO stands for "General Purpose IO". As it (GPIO with capital letters) has pre-defined meaning in the ESP32 Core/Environment (post #2), we may use gpio (with small letters) instead.

1 Like
8

yes i knew what GPIO stands for, thats why when i was declaring gpio pins i chose that name. i made the problem on my own xd. Also, thank you on your opinion about how to write a topic. it is the first time i open a discussion.
have a good weekend!

1 Like
9

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