Temperature result in serial monitor

Projects Programming
5

average = float (total) / float (numReadings) ;

More: https://stackoverflow.com/questions/16221776/why-dividing-two-integers-doesnt-get-a-float

... and ... this too for deeper understanding:
https://stackoverflow.com/questions/27674295/why-do-we-separately-cast-to-float-in-an-integer-division

Added ...
When dealing with casts, either of these two syntax will compile and provide the same answer:

#include <Streaming.h>

int a = 5;
int b = 4;

void setup() {
    Serial.begin(19200);
}

void loop() {

  float average = (a + b) / 2;
  
  Serial << "I Average=" << average << "\n";
  
  average = ((float) a + (float) b) / 2;

  Serial << "F1 Average=" << average << "\n";
    
  average = (float (a) + float (b)) / 2;
  
  Serial << "F2 Average=" << average << "\n";

}


> I Average=4.00
F1 Average=4.50
F2 Average=4.50