trying to assign an address for Ptr, get cannot convert 'char (*)[10]' to 'char*

Using Arduino Programming Questions
1

Hello again folks,

Well, I've been scolded for no address pointers and strcatting them and the like probably causing a SF or something... so I thought I had the solution to declare an char array for a char pointer and use that address:

Here is one function when I have two pointers and two char array addresses... but where am I going wrong?

void beepRepeatSet() {
  //BeepRepeatSet: Add 1x000 where x is 2^(x-1) times to repeat
  char *hertzA; <--- DECLARE ptr
  char h[10]; <--- DECLARE char array
  char r[10];
  hertzA = &h; <-- Assign address of h to hertzA results in error...
  char *hertzR;
  hertzR = &r;
  int hertzI, hertzLen;

hertzA = reinterpret_cast<char *>(hertz); //Convert long to char*
  hertzLen = strlen(hertzA);
  hertzR = hertzA;
  hertzI = atoi(hertzR);
  beepRepeat = 2 ^ (hertzI - 1);
  if ((hertzI < 2) || (hertzLen < 6)) beepRepeat = 0;
  //Serial.println(beepRepeat);
}
2

When you want a char * pointer to point to the beginning (element 0) of a char [] array, no & operator is necessary

hertzA = h;

When you want it to point to a specific element with index i, you can use either

hertzA = &h[i];

or

hertzA = h + i;

This also means that the original assignment can also be expressed as

hertzA = &h[0];

What you did in your code forms a pointer to the entire array, not a pointer to a specific element. Such pointer is incompatible with char * type. Hence the error.

In your code you are resorting to reinterpret_cast to defeat the language's type system and "fix" the incorrect use of & operator. Don't do this.

It is not clear what you are doing in your function though and whether you even need those pointers. So far you seem to be working with uninitialized (garbage) arrays.

3

Montmorency, thank you for your assistance with these coding woes of mine.