in this piece of code:
"temp = (number[++idx] - '0')"
could this be translated as:
temp=(number[idx])
idx=idx+1
but what does the -"0" mean?
in this piece of code:
"temp = (number[++idx] - '0')"
could this be translated as:
temp=(number[idx])
idx=idx+1
but what does the -"0" mean?
Convert an ASCII digit into its decimal value
No. The correct interpretation is
idx ++;
temp = (number[idx]);
temp = temp - '0';
It is likely that the value in temp will be the ascii code for a numeric digit - for example 51 for the digit 3. Subtracting the ascii code for the digit '0' (which is 48) converts the code into the number 3
...R
farolero777:
in this piece of code:
"temp = (number[++idx] - '0')"
could this be translated as:temp=(number[idx])
idx=idx+1
but what does the -"0" mean?
++idx causes idx to be incremented before its value us used so the two are not equivalent
The - '0' (note the single quotes) subtracts the value of '0' from the value on the left. This is often used to derive the numeric value of a digit from its ASCII value. Look at an ASCII table on line to see the values involved
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