Two inputs for Single output

Projects Programming
4

Okay, but why this part

Raghavendra431:
Now s2 is in off condition, if i toggle s2 to on state and then to off state light should off.
[/quote]
Why toggle it twice?
If you skip the toggle twice part (which sounds way easier to use) but just change the output state every time a switch changes (for example s1: on => out:on, s2:on => out:off, s1:off => out:on) it's also very easy.
```
**#include <Bounce2.h>

const byte OutputPin = 13; //calling it in1 is plain stupid
const byte SwitchPins[] = {5, 4}; //once you start numbering variables, use an array

Bounce switches[sizeof(SwitchPins)];

void setup()
{
  //setup the switches
  for(byte i = 0; i < sizeof(SwitchPins); i++){
    switches[i].attach(SwitchPins[i], INPUT_PULLUP); //use INPUT if you have external pull up/down resistors
  }

//setup the output
  pinMode(OutputPin, OUTPUT);
}

void loop()
{
  checkSwitches();
}

void checkSwitches()
{
  for(byte i = 0; i < sizeof(SwitchPins); i++){
    if(switches[i].update()){
      digitalToggle(OutputPin);
    }
  }
}

void inline digitalToggle(int pin){
  digitalWrite(pin, !digitalRead(pin));
}**

```