hello,
i am trying to build a circuit with around 2.5A and 24 V to operate 24V solenoids, motor and low side driver. please excuse my question if this is very obvious but i'm quite new to this.
i thought about using this DC DC converter : cincon CHB75
my battery supplies 14.8V.
the thing i don't understand is this : in the data sheet for the model CHB75-12S24 it says CAPACITOR LOAD MAX of 2000 microF what does it mean? how can i know if my circuit exceeds that?
thanks 
It means that if the circuit you are trying to power has in excess of 2000uF worth of capacitors on it then the converter will fail to start.
Add up all the capacitors in the circuit you are trying to power and see if it comes to below the maximum value.
so if i haven't included capacitors at all in my circuit - and looking and the data sheet for the motor and solenoids and none off them have capacities rating - should i be fine?
In this case a motor and a solenoid are inductors, that is they are anti capacitors. That means if you did have any capacitors the inductors would subtract from the total of the capacitors you have.
Yes this is fine if you have no capacitors at all.
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