Unexpected behavior of strcpy()

Projects Programming
9

It has taken me a while to figure it out, but in the end...
Here's the working code:

void copyToArray(char **arrayPtr, const char *strPtr)
{
  *arrayPtr = (char*) malloc(sizeof(char) * 20);
  
  strcpy(*arrayPtr, strPtr);
}

int main(int argc, const char * argv[])
{
  char *myA[3] = {"First string", "Second String", "Third string"};
  
  char strOne[20] = "";
  char strTwo[20] = "Hello my dear";
  
  char *ptrStrOne = NULL;
  
  ptrStrOne = strcpy(strOne, strTwo);
  
  copyToArray(&myA[1], ptrStrOne);

  //myA[1] = ptrStrOne;

  printf(" myA[1]: |%s|\n", myA[1]);           // |Fifth string|
  printf("*myA[1]: |%c|\n", *myA[1]);          // |F|
  printf("&myA[1]: |%p|\n\n", &myA[1]);        // |0x7ffeefbff3f8|

  ptrStrOne = strcpy(strOne, "&");
    
  printf(" myA[1]: |%s|\n", myA[1]);           // |&|
  printf("*myA[1]: |%c|\n", *myA[1]);          // |&|
  printf("&myA[1]: |%p|\n\n", &myA[1]);        // |0x7ffeefbff3f8|

  for (int i = 0; i < 3; i++)
  {
    printf("String: |%i| is: |%s|\n", i, myA[i]);   // |Fifth string|
  }
  return 0;
}

Output:
myA[1]: |Hello my dear|
*myA[1]: |H|
&myA[1]: |0x7ffeefbff3f8|

myA[1]: |Hello my dear|
*myA[1]: |H|
&myA[1]: |0x7ffeefbff3f8|

String: |0| is: |First string|
String: |1| is: |Hello my dear|
String: |2| is: |Third string|
Program ended with exit code: 0

Now I'm able to update/attach to strOne as much as I like and copy the contents of strOne to and element of the array.